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Mysql Nested Subqueries Problem » History » Version 4

Amber Herold, 03/04/2010 01:38 PM

1 1 Amber Herold
h1. Mysql Nested Subqueries Problem
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3 3 Amber Herold
This is the query that I wanted to do because it is easy to understand (= easier to maintain).
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Unfortunatly there is a bug in mysql (http://bugs.mysql.com/bug.php?id=10312) which makes this 
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so slow that no one has seen it complete. The subsequent query is a bit more difficult to follow
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but gets around this problem. 
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8 4 Amber Herold
<pre>
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SELECT ".DB_PROJECT.".projectexperiments.projectId 
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FROM ".DB_PROJECT.".projectexperiments 
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WHERE ".DB_PROJECT.".projectexperiments.name IN 
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( 
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    SELECT ".DB_LEGINON.".SessionData.name 
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    FROM ".DB_LEGINON.".SessionData 
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    WHERE ".DB_LEGINON.".SessionData.`DEF_id` IN 
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    ( 
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        SELECT ".DB_PROJECT.".shareexperiments.`REF|leginondata|SessionData|experiment` 
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        FROM ".DB_PROJECT.".shareexperiments 
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        WHERE ".DB_PROJECT.".shareexperiments.`REF|leginondata|UserData|user` = ".$userId." 
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    )
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);
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</pre>
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24 4 Amber Herold
<pre>
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SELECT amberproject.projectexperiments.projectId 
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FROM amberproject.projectexperiments 
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INNER JOIN 
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(
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    SELECT amberdbemdata.SessionData.name AS SessionName 
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    FROM amberdbemdata.SessionData 
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    INNER JOIN 
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    ( 		
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        SELECT amberproject.shareexperiments.`REF|leginondata|SessionData|experiment` AS SessionId 
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        FROM amberproject.shareexperiments 
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        WHERE amberproject.shareexperiments.`REF|leginondata|UserData|user` = ".$userId." 
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    ) AS SessionIds 
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    ON amberdbemdata.SessionData.`DEF_id` = SessionIds.SessionId 
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) AS SessionNames 
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ON amberproject.projectexperiments.name = SessionNames.SessionName;
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</pre>
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43 2 Amber Herold
See another example "here":http://forums.mysql.com/read.php?24,54721,54721#msg-54721.